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6x+x^2=832
We move all terms to the left:
6x+x^2-(832)=0
a = 1; b = 6; c = -832;
Δ = b2-4ac
Δ = 62-4·1·(-832)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-58}{2*1}=\frac{-64}{2} =-32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+58}{2*1}=\frac{52}{2} =26 $
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